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Mensuration

SSC-CGL Exams

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1. Introduction

Mensuration deals with length, area, surface area, and volume. SSC CGL questions are mostly formula-based, but visualization helps solve faster and avoid errors.

We divide it into:

1. 2D Geometry

Squares, rectangles, triangles, circles, polygons

2. 3D Geometry

Cubes, cuboids, cylinders, cones, spheres

2. 2D Geometry (Plane Figures)

Squares & Rectangles

Shape Area Perimeter Notes
Square A = a² P = 4a a = side
Rectangle A = l × b P = 2(l+b) l = length, b = breadth

Example 1

Square side = 8 cm → Area?

A = 8² = 64 cm²

64 cm²

Triangle

Type Area Formula Perimeter / Notes
Any triangle A = ½ × base × height -
Equilateral A = (√3/4)a² Perimeter = 3a
Right-angled A = ½ × perpendicular × base Hypotenuse = c

Example 2

Right triangle, base = 6 cm, height = 8 cm → Area

A = ½ × 6 × 8 = 24 cm²

Circle

Property Formula
Circumference C = 2πr
Area A = πr²
Diameter d = 2r

Example 3

Radius = 7 cm → Circumference & Area

C = 2π7 = 14π, A = π7² = 49π

3. 3D Geometry (Solids)

Cube

Volume: V = a³

Surface Area: SA = 6a²

Cuboid (Rectangular Box)

Volume: V = l × b × h

Surface Area: SA = 2(lb + bh + hl)

Cylinder

Volume: V = πr²h

Curved Surface Area: CSA = 2πrh

Total Surface Area: TSA = 2πr(h+r)

Cone

Volume: V = ⅓πr²h

Curved Surface Area: CSA = πrl

(l = slant height)

Total Surface Area: TSA = πr(l + r)

Sphere / Hemisphere

Shape Volume Surface Area
Sphere V = 4/3 πr³ SA = 4πr²
Hemisphere V = 2/3 πr³ SA = 3πr²

4. Visualization Tips

Draw a quick sketch — even rough — for each SSC problem.

Label dimensions (r, h, l, b, a) before substituting formulas.

Remember CSA vs TSA: CSA = only curved part; TSA = CSA + base(s).

For combined solids (cylinder + hemisphere), calculate separately, then sum.

5. Detailed Examples

Example 4: Cube & Cuboid

Cube side = 5 cm

V = 5³ = 125 cm³

SA = 6 × 25 = 150 cm²

Cuboid l=6, b=4, h=3

V = 6×4×3 = 72 cm³

SA = 2(24 + 12 + 18) = 108 cm²

Example 5: Cylinder

Radius = 7 cm, height = 10 cm

V = π7² × 10 = 490π cm³

CSA = 2π7×10 = 140π cm²

TSA = 2π7(10+7) = 238π cm²

Example 6: Cone

r = 5 cm, h = 12 cm

l = √(r² + h²) = √(25 + 144) = 13

CSA = πrl = 5π×13 = 65π cm²

TSA = πr(l + r) = π5(13+5) = 90π cm²

Example 7: Sphere / Hemisphere

r = 7 cm

Sphere: V = 4/3π343 ≈ 478.67π, SA = 4π49 = 196π

Hemisphere: V = 2/3π343 ≈ 228.67π, SA = 3π49 = 147π

6. SSC Short Tricks / Tips

Always check units: cm, m, or mm. Convert first.

For CSA vs TSA: visualize curved part only vs curved + base(s).

Combined solids → add volumes / surfaces.

Circle → circumference ~ 3.14 × 2r; area ~ 3.14 × r²

Memorize formula triangles (cube, cuboid, cylinder) for quick recall.

7. Practice Section

Q1. Square side = 12 cm → Area & Perimeter

View Answer

A = 12² = 144 cm², P = 4×12 = 48 cm

144 cm², 48 cm

Q2. Triangle base = 10 cm, height = 6 cm → Area

View Answer

A = ½ × 10 × 6 = 30 cm²

30 cm²

Q3. Circle radius = 14 cm → Area & Circumference

View Answer

A = π14² = 196π, C = 2π14 = 28π

196π, 28π

Q4. Cylinder r = 7 cm, h = 15 cm → Volume & CSA & TSA

View Answer

V = π7²×15 = 735π, CSA = 2π7×15=210π, TSA=2π7(15+7)=308π

735π, 210π, 308π

Q5. Cone r = 3 cm, h = 4 cm → l, CSA, TSA

View Answer

l = √(3²+4²)=5, CSA = π×3×5=15π, TSA=π3(5+3)=24π

l=5, CSA=15π, TSA=24π

Q6. Sphere radius = 10 cm → Volume & SA

View Answer

V = 4/3 π1000 ≈ 4186.67 cm³, SA = 4π100=400π

4186.67 cm³, 400π cm²

Q7. Hemisphere radius = 7 cm → Volume & SA

View Answer

V = 2/3 π343 ≈ 228.67π, SA = 3π49 = 147π

228.67π, 147π

8. Quick Recap Table

Shape Area / Volume Notes
Square Perimeter = 4a
Rectangle l×b P = 2(l+b)
Triangle ½ bh Equilateral = √3/4 a²
Circle πr², 2πr -
Cube a³, 6a² V, SA
Cuboid lbh, 2(lb+bh+hl) V, SA
Cylinder πr²h, 2πrh, 2πr(h+r) V, CSA, TSA
Cone ⅓πr²h, πrl, πr(l+r) l = √(r²+h²)
Sphere 4/3πr³, 4πr² -
Hemisphere 2/3πr³, 3πr² -

You've completed Article 10: Mensuration (2D & 3D Geometry)!

Courage Tip: Draw the solid or figure whenever possible. SSC loves combined solids, pipes, and circles inside squares, where visualization is key to faster solutions.

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